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Objective Questions with Answer for Mathematics (9) - मुफ्त [PDF] डाउनलोड करें

Last updated on Feb 12, 2026

पाईये मात्रात्मक रूझान उत्तर और विस्तृत समाधान के साथ MCQ प्रश्न। इन्हें मुफ्त में डाउनलोड करें मात्रात्मक रूझान MCQ क्विज़ Pdf और अपनी आगामी परीक्षाओं जैसे बैंकिंग, SSC, रेलवे, UPSC, State PSC की तैयारी करें।
Question 1:
Mathematics (9)

If ABC is an equilateral triangle and D,E,F are midpoints of BC,CA,AB respectively, then DEF is:

Scalene

Isosceles

Equilateral

Right-angled

View Answer & Solution
Correct Answer: C (Equilateral)C
Question 2:
Mathematics (9)

In right ABC (right angled at B ), if P and Q are points on AB and BC, then AQ2+CP2= :

AC2+PQ2

2AC2

AC2-PQ2

none of these

View Answer & Solution
Correct Answer: A (AC2+PQ2)A
Question 3:
Mathematics (9)

If the side BC of ABC is produced to D, the bisectors of ABC and ACD meet at E. Then BEC is:

A

2∠A

\(\frac{1}{2}\)A

\(90^{\circ}-\frac{1}{2} \angle A\)

View Answer & Solution
Correct Answer: C (\(\frac{1}{2}\)∠A)C
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Question 4:
Mathematics (9)

The line joining the midpoints of two sides of a triangle is ____ the third side.

equal to

half of

double of

triple of

View Answer & Solution
Correct Answer: B (half of)B
Question 5:
Mathematics (9)

In an isosceles triangle ABC with AB=AC,D and E are points on BC such that BE=CD. Then:

AD = AE

AD > AE

AD < AE

none of these

View Answer & Solution
Correct Answer: A (AD = AE)A
Question 6:
Mathematics (9)

If AB=QR,BC=PR and CA=PQ, then:

ABC ≅ △PQR

ABC ≅ △QRP

ABC ≅ △RPQ

CBA ≅ △PRQ

View Answer & Solution
Correct Answer: B (△ABC&nbsp;&cong; △QRP)B
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Question 7:
Mathematics (9)

In ABC, if B=30° and C=80°, and the bisector of A meets BC at D, then ADB is:

105°

115°

75°

90°

View Answer & Solution
Correct Answer: B (115&deg;)B
Question 8:
Mathematics (9)

The sum of the distances of any point in the interior of a triangle from its vertices is ____ the semi-perimeter.

less than

greater than

equal to

half of

View Answer & Solution
Correct Answer: B (greater than)B
Question 9:
Mathematics (9)

In ABC, the bisectors of B and C meet at O. Then BOC is:

\(90^{\circ}+\frac{1}{2} \angle A\)

\(90^{\circ}-\frac{1}{2} \angle A\)

\(180^{\circ}-\angle A\)

\(\frac{1}{2} \angle A\)

View Answer & Solution
Correct Answer: A (\(90^{\circ}+\frac{1}{2} \angle A\))A
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Question 10:
Mathematics (9)

If D is a point on the side BC of ABC such that AD>AC, then:

AD > AB

AB > AC

AB = AC

none of these

View Answer & Solution
Correct Answer: B (AB &gt; AC)B
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