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Question
Physics

When a metal surface is illuminated by light of wavelength λ the stopping potential is 8V. When the same surface is illuminated by light of wavelength 3λ, stopping potential is 2V. The threshold wavelength for this surface is-

4.5λ

जब किसी धातु की सतह पर λ तरंगदैर्घ्य (wavelength) वाला प्रकाश डाला जाता है, तो स्टॉपिंग पोटेंशियल 8V होता है। जब उसी सतह पर 3λ तरंगदैर्घ्य वाला प्रकाश डाला जाता है, तो स्टॉपिंग पोटेंशियल 2V होता है। इस सतह के लिए थ्रेशोल्ड तरंगदैर्घ्य (threshold wavelength) है-

4.5λ

View Answer & Solution
Correct Answer: A (9λ)
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