Question

Maths

Let m₁, m₂ be the slopes of two adjacent sides of a square of side a such that \((10(\cos \alpha-\sin \alpha), 10(\sin \alpha+\cos \alpha))\) . If one vertex of the square is (10(cos⁡α-sin⁡α),10(sin⁡α+cos⁡α)), where α∈\(\left(0, \frac{\pi}{2}\right)\) and the equation of one diagonal is \((\cos \alpha-\sin \alpha) x+(\sin \alpha+\cos \alpha) y=10, \text { then } 72\), then 72 sin⁴^⁡α+cos⁴⁡α+a²-3a+13 is equal to:

119

128

145

155

मान लें कि m₁ m₂ भुजा a वाले एक वर्ग की दो आसन्न भुजाओं की ढलान है जैसे कि \((10(\cos \alpha-\sin \alpha), 10(\sin \alpha+\cos \alpha))\) यदि वर्ग का एक शीर्ष (10( cos⁡ α - sin⁡ α ),10( sin⁡ α + cos⁡ α )) है जहाँ α ∈ \(\left(0, \frac{\pi}{2}\right)\) है और एक विकर्ण का समीकरण \((\cos \alpha-\sin \alpha) x+(\sin \alpha+\cos \alpha) y=10, \text { then } 72\) है, तो 72 बराबर है: 72 sin ⁴ ^⁡ α + cos ⁴ ⁡ α + a ² - 3 a +13

119

128

145

155

View Answer & Solution

Correct Answer: B (128)

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