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Maths

Bag I contains 3 red, 4 black and 3 white balls and Bag II contains 2 red, 5 black and 2 white balls. One ball is transferred from Bag I to Bag II and then a ball is draw from Bag II. The ball so drawn is found to be black in colour. Then the probability, that the transferred ball is red, is:

\(\frac{4}{9}\)

\(\frac{5}{18}\)

\(\frac{1}{6}\)

\(\frac{3}{10}\)

View Answer & Solution
Correct Answer: B (\(\frac{5}{18}\)) B
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