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Question
Physics

If K1 and K2 are the maximum kinetic energies of photoelectrons emitted when lights of wavelength λ1 and λ2 respectivelyare incidenton ametallic surface. If λ1=3λ2 , then:

\(K_1>\frac{K_2}{3}\)


\(K_1<\frac{K_2}{3}\)

\(K_1<\frac{K_2}{3}\)

\(\mathrm{K}_2=\frac{K_1}{3}\)

अगर K​1 और K​2, फोटोइलेक्ट्रॉन की मैक्सिमम काइनेटिक एनर्जी हैं, जो तब निकलती हैं जब λ1 और λ2 वेवलेंथ की लाइट किसी मेटल की सतह पर पड़ती हैं। अगर λ1=3λ2, तो:

\(K_1>\frac{K_2}{3}\)

\(\mathrm{K}_1=\frac{K_2}{3}\)

\(K_1<\frac{K_2}{3}\)

\(\mathrm{K}_2=\frac{K_1}{3}\)

View Answer & Solution
Correct Answer: C (\(K_1&lt;\frac{K_2}{3}\))
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