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Question

Physics

A long wire bent as shown in the figure carries current I. If the radius of the semicircular portion is a the magnetic induction at the centre O is:

\(\frac{\mu_0 I}{4 \pi a} \sqrt{\left(\pi^2-4\right)}\)

\(\frac{\mu_0 I}{4 a}+\frac{\mu_0 I}{2 \pi a}\)

\(\frac{\mu_0 I}{4 \pi a} \sqrt{\pi^2+4}\)

\(\frac{\mu_0 I}{4 a}\)

चित्र में दिखाए अनुसार मुड़ा हुआ एक लंबा तार I करंट ले रहा है। यदि सेमीसर्कुलर हिस्से का रेडियस a है, तो सेंटर O पर मैग्नेटिक इंडक्शन है:

\(\frac{\mu_0 I}{4 \pi a} \sqrt{\left(\pi^2-4\right)}\)

\(\frac{\mu_0 I}{4 a}+\frac{\mu_0 I}{2 \pi a}\)

\(\frac{\mu_0 I}{4 \pi a} \sqrt{\pi^2+4}\)

\(\frac{\mu_0 I}{4 a}\)

View Answer & Solution

Correct Answer: C (\(\frac{\mu_0 I}{4 \pi a} \sqrt{\pi^2+4}\))

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