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Mathematics (11)

A circle of constant radius ‘r’ passes through origin O and cuts the axes of coordinates in points P and Q, then find the equation of the locus of the foot of perpendicular from O to PQ.

(x2 + y2)2 (x–2 - y–2) = 4r2

(x2 - y2)2 (x–2 - y–2) = 4r2

(x2 - y2)2 (x–2 + y–2) = 4r2

x2 + y2)2 (x–2 + y–2) = 4r2

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Correct Answer: D (x2 + y2)2 (x–2 + y–2) = 4r2) D
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