Daily Quizzes
Mock Tests
Download MCQs Free PDF
Question
Mathematics (11)

Let S1 be a circle passing through A(0, 1), B(–2, 2) and S2 is a circle of radius units such that AB is common chord of S1 and S2. Find the equation of S2.

x2 + y2 + 2x – 3y - 2 ±\(\sqrt{7}\) (x + 2y – 2) = 0

x2 + y2 + 2x – 3y + 2 ±\(\sqrt{7}\) (x + 2y + 2) = 0

x2 + y2 + 2x – 3y + 2 ±\(\sqrt{7}\) (x + 2y – 2) = 0

x2 + y2 + 3x – 3y + 2 ±\(\sqrt{7}\) (x - 2y – 2) = 0

View Answer & Solution
Correct Answer: C (x2 + y2 + 2x – 3y + 2 ±\(\sqrt{7}\) (x + 2y – 2) = 0) C
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Trusted by 8.1 Crore+ Students

Exam Preparation Simplified

Learn Practice Analyse Improve
Get Started Free
Download the App

Trusted by 8.1 Crore+ Students

Enquire Now

Please share a few details to view the answer and solution.

×
Illustration of two people having a discussion

We're Here for You! Get in Touch with Class24 for All Your Needs!

Disclaimer: Your privacy is important to us. We will not share your information with third parties.