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Mathematics (11)

Find the equation of the circle which cuts each of the circles,  x² + y² = 4, x² + y² - 6x - 8y + 10 = 0 &  x² + y² + 2x - 4y - 2 = 0 at the extremities of a diameter.

x² + y² - 4x - 6y + 4 = 0

x² + y² - 4x + 6y - 4 = 0

x² + y² + 4x - 6y - 4 = 0

x² + y² - 4x - 6y - 4 = 0

View Answer & Solution
Correct Answer: D (x² + y² - 4x - 6y - 4 = 0) D
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