Question

Physics (11)

Three particles each of mass m are moving on a circle of radius r under mutual gravitational attraction. The speed of each particle is:

\(\sqrt{\frac{G m}{r}}\)

\(\sqrt{\frac{G m}{r}\left(1+\frac{1}{\sqrt{3}}\right)}\)

\(\frac{1}{2} \sqrt{\frac{G m}{r}(1+2 \sqrt{3})}\)

\(\sqrt{\frac{G m}{r \sqrt{3}}}\)

View Answer & Solution

Correct Answer: B (\(\sqrt{\frac{G m}{r}\left(1+\frac{1}{\sqrt{3}}\right)}\)) B

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