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Physics (11)

A satellite is in a circular orbit around the earth at a height R above the surface. If the satellite is stopped and allowed to fall, the speed with which it hits the surface is:

\(\sqrt{g R}\)

\(\sqrt{\frac{g R}{2}}\)

\(\sqrt{2 g R}\)

\(\sqrt{\frac{g R}{4}}\)

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Correct Answer: A (\(\sqrt{g R}\)) A
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