Question

Chemistry

For the reaction 2A + C -> B + 3D , the differential rate law can be written as

\(\frac{1}{2} \frac{d[A]}{d t}=\frac{-d[B]}{d t}=k[A]^x[B]^y\)

\(\frac{-d[A]}{d t}=\frac{1}{3} \frac{d[D]}{d t}=k[A]^x[D]^y\)

\(-\frac{1}{2} \frac{d[A]}{d t}=\frac{-d[C]}{d t}=k[A]^x[C]^y\)

\(-\frac{1}{2} \frac{d[A]}{d t}=\frac{d[B]}{d t}=k[A]^x[B]^y\)

रिएक्शन 2A + C -> B + 3D के लिए, डिफरेंशियल रेट लॉ को ऐसे लिखा जा सकता है

\(\frac{1}{2} \frac{d[A]}{d t}=\frac{-d[B]}{d t}=k[A]^x[B]^y\)

\(\frac{-d[A]}{d t}=\frac{1}{3} \frac{d[D]}{d t}=k[A]^x[D]^y\)

\(-\frac{1}{2} \frac{d[A]}{d t}=\frac{-d[C]}{d t}=k[A]^x[C]^y\)

\(-\frac{1}{2} \frac{d[A]}{d t}=\frac{d[B]}{d t}=k[A]^x[B]^y\)

View Answer & Solution

Correct Answer: C (\(-\frac{1}{2} \frac{d[A]}{d t}=\frac{-d[C]}{d t}=k[A]^x[C]^y\))

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