Question

Mathematics (9)

If the side BC of △ABC is produced to D, the bisectors of ∠ABC and ∠ACD meet at E. Then ∠BEC is:

∠A

2∠A

\(\frac{1}{2}\)∠A

\(90^{\circ}-\frac{1}{2} \angle A\)

View Answer & Solution

Correct Answer: C (\(\frac{1}{2}\)&ang;A) C

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