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The digit in unit's placeof product \((2464)^{1793} \times (615)^{317}\times (131)^{491}\) is

0

2

3

5

\((2464)^{1793} \times (615)^{317}\times (131)^{491}\) के गुणनफल में इकाई स्‍थान पर कौन सा अंक होगा ?

0

2

3

5

View Answer & Solution
Correct Answer: A (0)
Detailed Solution:

\((2464)^{1793} \times (615)^{317}\times(131)^{491}\)

41 = 4 = 4

42 = 16 = 6

43 = 64 = 4

                    \((2464)^{1793} \times (615)^{317}\times(131)^{491}\)

                 Odd power

Unit digit        4          X 5     X              1 = 20

=> 20 = 0 Unit

\((2464)^{1793} \times (615)^{317}\times(131)^{491}\)

41 = 4 = 4

42 = 16 = 6

43 = 64 = 4

                    \((2464)^{1793} \times (615)^{317}\times(131)^{491}\)

                विषम घात 

इकाई अंक        4          X 5     X              1 = 20

=> 20 = 0 इकाई

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